The magnetic field in a plane electromagnetic | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The general equation for a plane electromagnetic wave is given by $B = B_{0} \sin (kx + \omega t)$.Comparing this with the given equation $B_{y} =

Vedclass · Accepted Answer

$2 	imes 10^{-3} \; m$

Vedclass · Answer

(A) The general equation for a plane electromagnetic wave is given by $B = B_{0} \sin (kx + \omega t)$.Comparing this with the given equation $B_{y} = 2 	imes 10^{-7} \sin (\pi 	imes 10^{3} x + 3 \pi 	imes 10^{11} t) \; T$, we identify the wave number $k$ as:$k = \pi 	imes 10^{3} \; 	ext{rad/m}$.The relationship between the wave number $k$ and the wavelength $\lambda$ is given by $k = \frac{2\pi}{\lambda}$.Substituting the value of $k$:$\pi 	imes 10^{3} = \frac{2\pi}{\lambda}$.Solving for $\lambda$:$\lambda = \frac{2\pi}{\pi 	imes 10^{3}} = 2 	imes 10^{-3} \; m$.

The magnetic field in a plane electromagnetic wave is given by, $B_{y} = 2 \times 10^{-7} \sin (\pi \times 10^{3} x + 3 \pi \times 10^{11} t) \; T$. Calculate the wavelength.

Similar Questions

$A$ point source of $100\,W$ emits light with $5\%$ efficiency. At a distance of $5\,m$ from the source,the intensity produced by the electric field component is:

Electromagnetic waves are:

If ${\varepsilon _0}$ and ${\mu _0}$ are respectively the electric permittivity and the magnetic permeability of free space,and ${\varepsilon}$ and ${\mu}$ are the corresponding quantities in a medium,the refractive index of the medium is:

Assertion : Radio waves can be polarised.
Reason : Sound waves in air are longitudinal in nature.

$A$ plane electromagnetic wave is incident on a plane surface of area $A$ normally,and is perfectly reflected. If energy $E$ strikes the surface in time $t$,then the average pressure exerted on the surface is ($c=$ speed of light).

Vedclass Test Series

Exam Paper Generator

Online Exam Module